b>0, \alpha<0 => a^\alpha>b^\alpha, \\ \frac{1}{8}<\frac{1}{2}<1<2<4, \\ (\frac{1}{8})^{-\frac{1}{2}}>(\frac{1}{2})^{-\frac{1}{2}}>1^{-\frac{1}{2}}>2^{-\frac{1}{2}}>4^{-\frac{1}{2}}, \\ 4^{-\frac{1}{2}}=\frac{1}{\sqrt4}=\frac{1}{2}." alt="a>b>0, \alpha<0 => a^\alpha>b^\alpha, \\ \frac{1}{8}<\frac{1}{2}<1<2<4, \\ (\frac{1}{8})^{-\frac{1}{2}}>(\frac{1}{2})^{-\frac{1}{2}}>1^{-\frac{1}{2}}>2^{-\frac{1}{2}}>4^{-\frac{1}{2}}, \\ 4^{-\frac{1}{2}}=\frac{1}{\sqrt4}=\frac{1}{2}." align="absmiddle" class="latex-formula">