28ab+ (2a-7b)вквадрате; a=5 ; b= 1/7

Question

28ab+ (2a-7b)вквадрате; a=5 ; b= 1/7

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Answer 1

28ab+4a^2-28ab+49b^2=4a^2+49b^2=4*5^2+49*(1/7)^2=4*25+49/1*1/49=101