ПОМОГИТЕ РЕШИТЬ ( НА ФОТО)
= 1+ (-3/4)²=\frac{1}{ cos \beta ^{2} \frac{25}{16}= \frac{1}{ cos^{2 } \beta } ; cos \beta = \sqrt{ \frac{9}{25} } = -\frac{3}{5} ; sinβ = √41/5; ctgβ = 3/4; б) 1+ctg²β =1/sin²β; 1+ 25/144 = 1/sin²β; sinβ= √169/144 = 13/12;