Помогите по алгебре

Question

Помогите по алгебре

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Answer 1

(1ц 11/25)^(-0.5) ·(4ц17/27)^(-1/3) = (36/25)^(-0.5) · (125/27)^(-1/3)  =
= (25/36)^0.5 · (27/125)^(1*3) = √(25/36) · ∛(27/125) = 5/6 · 3/5 = 1/2

(a - b)/(a^1/2 - b^1/2) = ((√a)² - (√b)²)/(√a - √b) =
= (√a + √b)(√a - √b) / (√a - √b) =
= (√a + √b)