а) (-3x+1)⋅(2x-7) >0
-3x+1=0⇒3x=1⇒x=1/3
2x-7=0⇒2x=7⇒x=3,5
_ + _
--------------------(1/3)----------------(3,5)------------------
x∈(1/3;3,5)
б) -8x²+6x>0
8x²-6x<0<br>2x(4x-3)=0
x=0 x=3/4
+ _ +
--------------------(0)----------------(3/4)------------------
x∈(0;3/4)