Помогите решить 1 и 3
1 ОДЗ {x>0 {x≠1 x∈(0;1) U (1;∞) перейдем к основанию 2 log(2)x+2/log(2)x -3<0<br>log(2)x=a (a²-3a+2)/a<0<br>a²-3a+2=0⇒a1+a2=3 U a1*a2=2⇒a1=1 U a2=2 a=0 _ + _ + -------------------(0)---------------(1)---------------------(2)-------------------- a<0⇒log(2)x<0⇒x<1<br>1x∈(0;1) U (2;4) 3 ОДЗ x²+3x-10>0 x1+x2=-3 U x1*x2=-10⇒x1=-5 U x2=2 x∈(-∞;-5) U (2;∞) log(9)[(x+5)^7*(x-2)^7]-log(9)[(x-2)^7/(x+5)]≤8 log(9)[(x+5^7*(x-2)^7*(x+5)/(x-2)^7]≤8 log(9)(x+5)^8≤8 8log(9)(x+5)≤8 log(9)(x+5)≤1 x+5≤9 x≤4 x∈(-∞;-5) U (2;4]