Найти пройзводную 3^3корень из x+2/x^2-2x^3+3

если так выглядит

$\frac{3^{3}\sqrt{x+2}}{x^{2}-2x^{3}+3}$ , то

( $\frac{3^{3}\sqrt{x+2}}{x^{2}-2x^{3}+3}$ )'= $\frac{(3^{3}\sqrt{x+2})'*(x^{2}-2x^{3}+3)-(3^{3}\sqrt{x+2})*(x^{2}-2x^{3}+3)'}{(x^{2}-2x^{3}+3)^2}$ = $\frac{27x\frac{1}{\sqrt{x+2}}*(x^{2}-2x^{3}+3)-(3^{3}\sqrt{x+2})*(2x-6x^{2})}{(x^{2}-2x^{3}+3)^2}=$ $\frac{\frac{27x^{3}-54x^{4}+81x}{\sqrt{x+2}}-(3^{3}\sqrt{x+2})*(2x-6x^{2})}{(x^{2}-2x^{3}+3)^2}=$ $\frac{{27x^{3}-54x^{4}+81x}-\sqrt{x+2}(3^{3}\sqrt{x+2})*(2x-6x^{2})}{\sqrt{x+2}(x^{2}-2x^{3}+3)^2}$ = $\frac{{27x^{3}-54x^{4}+81x}-27(x+2)*(2x-6x^{2})}{\sqrt{x+2}(x^{2}-2x^{3}+3)^2}=$ $\frac{{27x^{3}-54x^{4}+81x}-27(-6x^{3}-10x^{2}+4x)}{\sqrt{x+2}(x^{2}-2x^{3}+3)^2}=$ $\frac{{27x^{3}-54x^{4}+81x}-(-162x^{3}-270x^{2}+108x)}{\sqrt{x+2}(x^{2}-2x^{3}+3)^2}$ = $\frac{{189x^{3}-216x^{4}-27x}}{\sqrt{x+2}(x^{2}-2x^{3}+3)^2}$