(x^2-5x)^2+10x^2-50x+24=0

Question

(x^2-5x)^2+10x^2-50x+24=0

Answer 1

(x²-5x)²+10(x²-5x)+24=0
x²-5x=a
a²+10a+24=0
a1+a2=-10 U a1*a2=24
a1=-6⇒x²-5x=-6
x²-5x+6=0
x1+x2=5 U x1*x2=6
x1=2 U x2=3
a2=-4⇒x²-5x=-4
x²-5x+4=0
x1+x2=5 U x1*x2=4
x1=1 U x2=4
 Ответ x={1;2;3;4}

Answer 2

Решение во вложении...................

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