+ \infty \frac{4x^2-x+4}{5x^2+1}=\frac{4-\frac{1}{x}+\frac{4}{x^2}}{5+\frac{1}{x^2}}=\frac{4}{5}" alt="lim \ x->+ \infty \frac{4x^2-x+4}{5x^2+1}=\frac{4-\frac{1}{x}+\frac{4}{x^2}}{5+\frac{1}{x^2}}=\frac{4}{5}" align="absmiddle" class="latex-formula">
Ответ
