2(х-3)-5=4х
2х-6-5-4х=0
-2х=11
х=-5.5
\frac{x*(х-5)}{(х+5)*(х-5)} + \frac{(x+5)(х+5)}{(Х-5)(х+5)} = \frac{50}{х^2-25}
\frac{x^2-5x+x^2+25-50}{x^2-25}=0
\frac{2x^2-5x-25}{x^2-25}=\frac{2(x-5)(x+\frac{5}{2})}{(x-5)(x+5)}=\frac{(x-5)(x+5)}{(x-5)(x+5)}=1
2X^2-5x-25=0
D=25-4*2*(-25)
D=225
x1= \frac{5+15}{4}=5
x2=\frac{5-15}{4}=-\frac{5}{2}