Решить уравнения, помогите пожалууйста!!1) 3х в квадрате-14х+16--02) м в...

$3x^{2} -14x+16=0$
$a=3,b=-14,c=16$

0" alt="D= b^{2} -4ac=( -14) ^{2} -4*3*16=4= 2^{2} >0" align="absmiddle" class="latex-formula">
$x_{1,2} = \frac{-b+- \sqrt{D} }{ {2a} }$
$x_{1} = \frac{14- \sqrt{ 2^{2} } }{2*3} =2$
$x_{2} = \frac{14+ \sqrt{ 2^{2} } }{2*3} = \frac{8}{3} =2,7$

$m^{2} +2m-80=0$
$a=1,b=2,c=-80$

0" alt="D= 2^{2} -4*1*(-80)=324= 18^{2} >0" align="absmiddle" class="latex-formula">
$x_{1} = \frac{-2- \sqrt{ 18^{2} } }{2*1} =-10$
$x_{2} = \frac{-2+ \sqrt{ 18^{2} } }{2*1} =8$

$7 y^{2} -20y+14=0$
$a=7,b=-20,c=14$

0" alt="D=(-20) ^{2} -4*7*14=8>0" align="absmiddle" class="latex-formula">
$x_{1} = \frac{=20- \sqrt{8} }{2*7} = \frac{20- \sqrt{8} }{14}$
$x_{2} = \frac{20+ \sqrt{8} }{2*7} = \frac{20+ \sqrt{8} }{14}$

$4x^{2} -36x+4,5=0$
$a=4,b=-36,c=4,5$

0" alt="D= (\frac{b}{2} ) ^{2}-a*c= 324-4*4,5=306>0" align="absmiddle" class="latex-formula">
$x_{1} = \frac{ \frac{36}{2}- \sqrt{306} }{4} = \frac{18- \sqrt{306} }{4}$
$x_{2} = \frac{ \frac{36}{2}+ \sqrt{306} }{4} = \frac{18+ \sqrt{306} }{4}$

$y^{2} -10y-25=0$
$a=1,b=-10,c=-25$

0" alt="D=(-10) ^{2} -4*1*(-25)=200>0" align="absmiddle" class="latex-formula">
$x_{1} = \frac{10- \sqrt{200} }{2}$
$x_{2} = \frac{10+ \sqrt{200} }{2}$