Решите уравнение -x^2+6x-7=0

Question

Решите уравнение -x^2+6x-7=0

Answer 1

0 \\ x_{1} = \frac{6+ \sqrt{36-28} }{2} = \frac{6+ \sqrt{8} }{2} = \frac{2(3+ \sqrt{2} )}{2} =3+ \sqrt{2} \\ x_{2} = \frac{6- \sqrt{36-28} }{2} = \frac{6- \sqrt{2} }{2} = \frac{2(3- \sqrt{2}) }{2} =3- \sqrt{2} " alt=" x^{2} -6x+7=0 \\ D>0 \\ x_{1} = \frac{6+ \sqrt{36-28} }{2} = \frac{6+ \sqrt{8} }{2} = \frac{2(3+ \sqrt{2} )}{2} =3+ \sqrt{2} \\ x_{2} = \frac{6- \sqrt{36-28} }{2} = \frac{6- \sqrt{2} }{2} = \frac{2(3- \sqrt{2}) }{2} =3- \sqrt{2} " align="absmiddle" class="latex-formula">

Answer 2

(x-1)(x+7)=0
x1=1
x2=7

Comments

ага тока в ответе должны получится корни