(6x-12/x^2+2x-8)+x-3=0

Question

(6x-12/x^2+2x-8)+x-3=0

Answer 1

X2+2x-8=(x-2)(x+4)
x1+x2=-2 U x18x2=-8⇒x1=-4 U x2=2
6(x-2)/(x-2)(x+4) + (x-3)=0
6/(x+4) + (x-3)=0      x≠2  x≠-4
6-(x-3)(x+4)=0
6+x²-3x+4x-12=0
x²+x-6=0
x1+x2=-1 U x1*x2=-6
x1=-3
x2=2-не удов усл
Ответ х=-3