Решите систему уравнения: {y+4/x=-2 {x-6/y=6

$\left \{ {{y+ \frac{4}{x} =-2} \atop {x- \frac{6}{y} =6}} \right. \\ \left \{xy+4 =-2x} \atop {xy-6 =6y}} \right. \\ \left \{y= \frac{- 2x -4}{x} } \atop {xy-6 =6y}} \right. \\ x *\frac{- 2x -4}{x} }-6 =6 *\frac{- 2x -4}{x} } \\ -2x^2-4x-6x=-12x-24 \\ -2x^2+2x+24=0 \\ x^2-x-12=0$
$x^2-x-12=0 \\ D=1+4*12=49 \\ \sqrt{D} =7 \\ x_1=(1-7)/2=-3 \\$
$y_1=(-2*(-3)-4)/(-3)=-2/3 \\ x_2=(1+7)/2=4 \\ y_2=(-2*4-4)/4=-3$
Ответ: x=-3; y=-2/3 или x=4; y=-3