Помогите пожалуйста>< Даю 30 баллов!

Решите задачу:

$1)\; \; \dfrac{(12\sqrt3)^2}{9}=\dfrac{144\cdot 3}{9}=48\\\\\\2)\; \; \sqrt{\dfrac{4}{81}}-\sqrt{\dfrac{1}{36}}=\dfrac{2}{9}-\dfrac{1}{6}=\dfrac{4-3}{18}=\dfrac{1}{18}\\\\\\3)\; \; (7-\sqrt3)(7+\sqrt3)=7^2-(\sqrt3)^2=49-3=46$

$4)\; \; (\sqrt5-\sqrt3)^2=5-2\, \sqrt{5\cdot 3}+3=8-2\sqrt{15}\\\\\\5)\; \; 5\sqrt{0,04}-\dfrac{1}{16}\sqrt{100}=5\cdot 0,2-\dfrac{10}{16}=1-0,625=0,375\\\\\\6)\; \; 8\sqrt2-3\sqrt{50}+2\sqrt{32}=8\sqrt2-3\cdot 5\sqrt2+2\cdot 4\sqrt2=-15\sqrt2\\\\\\7)\; \; \dfrac{\sqrt{125}}{\sqrt5}=\sqrt{\dfrac{125}{5}}=\sqrt{25}=5\\\\\\8)\; \; \sqrt{2^0\cdot 6^6}=\sqrt{1\cdot (6^3)^2}=6^3=216$