Помогите пжжж…срочнооо
x = \pi + 2\pi n, n \in Z" alt="2cos^2x - cosx - 3 =0\\2(cosx+1)(cosx-\frac{3}{2}) = 0\\cosx = -1 => x = \pi + 2\pi n, n \in Z" align="absmiddle" class="latex-formula">
У второго некорректно условие.
x = \pi + 2\pi n, n \in Z" alt="2cos^2x - cosx - 3 =0\\2(cosx+1)(cosx-\frac{3}{2}) = 0\\cosx = -1 => x = \pi + 2\pi n, n \in Z" align="absmiddle" class="latex-formula">