СРОЧНО Пожалуйста Решите

Question 1

Question 2

x\\ 25x^2>16\end{cases}" alt="\begin{cases}5x>x\\ 25x^2>16\end{cases}" align="absmiddle" class="latex-formula">

0\\ 25x^2-16>0\ /:25\end{cases}" alt="\begin{cases}5x-x>0\\ 25x^2-16>0\ /:25\end{cases}" align="absmiddle" class="latex-formula">

0\ /:4\\ x^2- \frac{16}{25} >0\end{cases}" alt="\begin{cases}4x>0\ /:4\\ x^2- \frac{16}{25} >0\end{cases}" align="absmiddle" class="latex-formula">

0\\ (x- \frac{4}{5} )(x+ \frac{4}{5} )>0\end{cases}" alt="\begin{cases}x>0\\ (x- \frac{4}{5} )(x+ \frac{4}{5} )>0\end{cases}" align="absmiddle" class="latex-formula">

$\begin{cases}x\in(0;+\infty)\\ x\in \left( -\infty;- \frac{4}{5} \right) \cup \left( \frac{4}{5};+\infty \right) \end{cases}$

$x\in \left( \frac{4}{5};+\infty \right)$

Ответ:

$x\in \left( \frac{4}{5};+\infty \right)$

Question 3

спасибо!

Question 4

:)

7x8_zn · Answer 1 · 2020-06-02T07:26:38+0000

x\\ 25x^2>16\end{cases}" alt="\begin{cases}5x>x\\ 25x^2>16\end{cases}" align="absmiddle" class="latex-formula">

0\\ 25x^2-16>0\ /:25\end{cases}" alt="\begin{cases}5x-x>0\\ 25x^2-16>0\ /:25\end{cases}" align="absmiddle" class="latex-formula">

0\ /:4\\ x^2- \frac{16}{25} >0\end{cases}" alt="\begin{cases}4x>0\ /:4\\ x^2- \frac{16}{25} >0\end{cases}" align="absmiddle" class="latex-formula">

0\\ (x- \frac{4}{5} )(x+ \frac{4}{5} )>0\end{cases}" alt="\begin{cases}x>0\\ (x- \frac{4}{5} )(x+ \frac{4}{5} )>0\end{cases}" align="absmiddle" class="latex-formula">

$\begin{cases}x\in(0;+\infty)\\ x\in \left( -\infty;- \frac{4}{5} \right) \cup \left( \frac{4}{5};+\infty \right) \end{cases}$

$x\in \left( \frac{4}{5};+\infty \right)$

Ответ:

$x\in \left( \frac{4}{5};+\infty \right)$