ПОМОГИТЕ С АЛГЕБРОЙ ПЖ ( СОКРАЩЕНИЕ ДРОБЕЙ 8КЛАСС) 30 БАЛЛОВ

Решите задачу:

$1)\frac{x {}^{3} + 8 }{6x {}^{2} + 11x - 2 } = \frac{(x + 2)(x {}^{2} - 2x + 4)}{6(x - \frac{1}{6})(x + 2) } = \frac{x {}^{2} - 2x + 4}{6x - 1} \\ \\ 6x {}^{2} + 11x - 2 = 0 \\ d = 121 + 48 = 169 \\ x = \frac{1}{6} \: \: \: x = - 2$

$2) \frac{x {}^{2} - 4}{5x - x {}^{2} - 6} = - \frac{(x - 2)(x +2 )}{(x - 2)(x - 3)} = - \frac{x + 2}{x - 3} \\ \\ - x {}^{2} + 5x - 6 = 0 \\ d = 25 - 24 = 1 \\ x = 2 \: \: \: \: x = 3$

$3) \frac{x {}^{2} + 2x - 15 }{4x - x {}^{2} - 3 } = \frac{(x + 5)(x - 3)}{ - (x - 1)(x - 3)} = \frac{x + 5}{ - x + 1} \\ \\ x {}^{2} + 2x - 15 = 0 \\ d = 4 + 60 = 64 \\ x = - 5 \: \: \: x = 3 \\ \\ 4x - x {}^{2} - 3 = 0 \\ d = 16 - 12 = 4 \\ x = 1 \: \: \: x = 3$