0\\\\x>-4\\\\2)4+x\leq0,2^{-1}\\\\4+x\leq5\\\\x\leq 1\\\\x\in(-4;1]" alt="6)log_{0,2} (4+x)\geq-1\\\\1)4+x>0\\\\x>-4\\\\2)4+x\leq0,2^{-1}\\\\4+x\leq5\\\\x\leq 1\\\\x\in(-4;1]" align="absmiddle" class="latex-formula">
-1" alt="7)log_{0,5}(x^{2}-5x+6)>-1" align="absmiddle" class="latex-formula">
ОДЗ :
x² - 5x + 6 > 0
(x - 3)(x - 2) > 0
+ - +
____________₀________₀_________
2 3
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x ∈ (- ∞ ; 2) ∪ (3 ; + ∞)
+ - +
___________₀_____________₀____________
1 4
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x ∈ (1 ; 4)
С учётом ОДЗ окончательный ответ :
x ∈ (1 ; 2) ∪ (3 ; 4)