3x³-10x²- 9x+ 4 =0
(3x³-10х²) - (9x-4)=0
x²*(3x-10)-(9x-4)=0
x²*(3x-10+6x-6x+6-6)-(9x - 4)=0
x²((9x-4)-(6x+6))-(9x-4)=0
x²*(9x-4) - x²(6x+6)-(9x-4)=0
(9x-4) (x²-1) - 6x² (x+1)=0
(9x-4)(x-1)(x+1)-6x²(x+1)=0
(x+1)*((9x-4)(x-1) -6x²)=0
(x+1)(9x²-4x- 9x+4-6x²)=0
(x+1)(3x²-13x+4)=0
x+1=0 или 3x²-13x+4=0
х₁=-1 D=169-48=121 √D=11
x₂=(13+11)/6=4
x₃=(13-11)/6= 1/3
Ответ : x₁=-1; x₂=4; x₃=1/3