Сократите дробь a) (n+1)!/n! b) n!/(n+2)! B) (n+1)! (n+3)/(n+4)!

Question

Сократите дробь a) (n+1)!/n! b) n!/(n+2)! B) (n+1)! (n+3)/(n+4)!

Answer 1

a) (n+1)!/n!=(n+1)n!/n!=(n+1) 

 

b) n!/(n+2)!=n!/((n+2)n!)=1/(n+2) 

 

B) (n+1)!(n+3)/(n+4)!= (n+1)!(n+3)/((n+1)!(n+2)(n+3)(n+4))=1/((n+2)(n+4))