Известно, что х+ 1/х=a. Найти х^3+1/х^3

Решите задачу:

$\displaystyle \tt x^3+\frac{1}{x^3}=\bigg(x+\frac{1}{x}\bigg)\bigg(x^2-x\cdot\frac{1}{x}+\frac{1}{x^2}\bigg)=\bigg(x+\frac{1}{x}\bigg)\bigg(x^2+\frac{1}{x^2}-1\bigg)=\\ \\ \\ =\bigg(x+\frac{1}{x}\bigg)\bigg(x^2+2x\cdot\frac{1}{x}+\frac{1}{x^2}-2x\cdot\frac{1}{x}-1\bigg)=\bigg(x+\frac{1}{x}\bigg)\bigg(\bigg(x+\frac{1}{x}\bigg)^2-3\bigg)=\\ \\ \\ =a\cdot (a^2-3)=a^3-3a$