ООФ:
0 \\ 35-2x-x^2\geq 0\end{array}} \ \Leftrightarrow \ \left\{\begin{array}{I} (x-5)(x+6)<0 \\ (x-5)(x+7)\leq 0 \end{array}} \ \Leftrightarrow \ \left\{\begin{array}{I} x \in (-6; \ 5) \\ x \in [-7; \ 5] \end{array}} " alt=" \left\{\begin{array}{I} 30-x-x^2>0 \\ 35-2x-x^2\geq 0\end{array}} \ \Leftrightarrow \ \left\{\begin{array}{I} (x-5)(x+6)<0 \\ (x-5)(x+7)\leq 0 \end{array}} \ \Leftrightarrow \ \left\{\begin{array}{I} x \in (-6; \ 5) \\ x \in [-7; \ 5] \end{array}} " align="absmiddle" class="latex-formula">
x∈(-6; 5)
Ответ: 4