{x+y=4
{(x+2)/(y-3)+(y+2)/(x-3)=-8
одз x≠3 y≠3
{x+y=4
{(x+2)(x-3)+(y-3)(y+2)=8(y-3)(x-3)
{y=4-x
{(x+2)(x-3)+(4-x-3)(4-x+2)=8(4-x-3)(x-3)
{y=4-x
{x²+2x-3x-6+(1-x)(6-x)=8(1-x)(x-3)
{y=4-x
{x²-x-6+6-6x-x+x²=8(x-x²+3x-3)
{y=4-x
{2x²-8x=-8x²+32x-24
{y=4-x
{10x²-40x+24=0
{y=4-x
{5x²-20x+12=0 D=400-400=0 x=20/10=2
{y=4-x
{x=2
{y=4-2=2
{x=2
ответ (2;2)