Ctg(3α)=-1/2; sin(6α)-?
sin(6α)=2sin(3α) *cos(3α)
1+ctg^2 (3α)=1/sin^2 (3α); 1/sin^2 (3α)=1+(-1/2)^2;1/sin^2 (3α)=5/4;
sin^2(3α)=4/5; sin(3α)=+-2√5 /5=+-0,4√5
sin^2 (3α) +cos^2 (3α)=1; cos^2 (3α)=1-4/5=1/5; cos(3α)=+-√5 /5;
sin(6α)=2(+-0,4√5) *(+-√5 /5)=+-2*0,4 *5 /5=+-0,8
Ответ +-0,8