Решите пж : 10* ( 1-2х ) = 5* ( 2х-3 ) -3 ( 11х-5 )

Question

Решите пж : 10* ( 1-2х ) = 5* ( 2х-3 ) -3 ( 11х-5 )

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Answer 1

1)(5х-3)+(7х-4)=8-(15-11х)
5х-3+7х-4=8-15+11х
х=0
2)(4х+3)-(10х+11)=7+(13-4х)
4х+3-10х-11=7+13-4х
-2х=28
Х=-14
3)(7-10х)-(8-8х)+(10х+6)=-8
7-10х-8+8х+10х+6=-8
8х=13
Х=13/8