-a²·4a³= 0,5x²·y·(xy) 11a⁵-8a⁵+3a⁵+a⁵= 20xy+5xy-17xy

Question

-a²·4a³=
0,5x²·y·(xy)
11a⁵-8a⁵+3a⁵+a⁵=
20xy+5xy-17xy

Answer 1

-a²·4a³=-4a^5
0,5x²·y·(xy)=0,5x³y²
11a⁵-8a⁵+3a⁵+a⁵=7a^5
20xy+5xy-17xy=8xy