Вычислить массовые доли элементов соединениях а)Ba(OH)2 б) Al(MaO4)3
Mr(Ba(OH)2) = 137+2*16+2*1 = 171 W(Ba) = 137/171 = 0.80=80% W(O) = 32/171 = 0.19=19% W(H)=2/171=0.01=1% Mr(Al(SO4)3) = 27+3*32+12*16 = 315 W(Al) = 27/315 = 0.09=9% W(S) = 96/315=0.30=30% W(O)= 192/315 = 0.61=61%