Task/25526704
-------------------
сократить:
(2x² -7x +3) /(x -2x²) = 2(x-1/2)(x-3) / (-2x(x -1/2) ) =
- (x-3) / x или (3- x) /x или (3/ x) - 1.
---------------
(2 -x +√x ) /(√x -2) =(-x +√x +2) /(√x -2) = - (x - √x -2) /(√x -2) =
- ((√x)² - √x -2) /(√x -2) = -(√x +1)(√x -2) / (√x -2) = - (√x +1) .
------- P.S.-------
* * ax² +bx +c=a(x-x₁)(x - x₂), где x₁ и x₂ корни уравнения ax² +bx +c=0* *
t² -t -2 =0 ; D = 1² -4*1*(-2)=1+8 =9 =3²
t₁ =(1-3)/2 = -1;
t₂ =(1 +3)/2 =2 .
t² - t - 2 =(t -t₁)(t -t₂) =(t +1)(t -2) если t = √x ||
(√x)² - √x -2 =(√x +1)(√x -2)