Помогите,пожалуйста!!!!

Решите задачу:

$\frac{y}{x}=-\frac{1}{2}\\\\ \frac{x^3y^3-y^6}{x^6+23x^3y^3} =\Big [ \frac{:x^6}{:x^6} \Big ]= \frac{(\frac{y}{x})^3-(\frac{y}{x})^6}{1+23\cdot (\frac{y}{x})^3} = \frac{(-\frac{1}{2})^3-(-\frac{1}{2})^6}{1+23\cdot (-\frac{1}{2})^3} = \frac{-\frac{1}{8}-\frac{1}{64}}{1-23\cdot \frac{1}{8}} =\\\\= \frac{-9\cdot 8}{64\cdot (-15)} =\frac{3}{8\cdot 5}= \frac{3}{40}=0,075$