Выполнить деление: 3-2i/3+2i
(3-2i)/(3+2i)=(3-2i)²/[(3-2i)(3+2i)=(9-12i+4i²)/(9-4i²)=(9-12i-4)/(9+4)= =(5-12i)/13=5/13-12/13*i
(3-2i)/(3+2i)=(3-2i)²/(3+2i)(3-2i)=(9-12i-4)/ (9+4)=(5-12i)/13=5/13-12/13i