Помогите плиз!!!!¡!!!!!!!!!!!!!!!!

Question

Помогите плиз!!!!¡!!!!!!!!!!!!!!!!

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Comments

1) а) 27 б) 38 в) 14 г) 56

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2) CuO, Na2O, Fe2O3

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3) a) 2Cu+O2=2CuO б) Cu(OH)2 = CuO +H2O

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4) 4Na +O2 = 2Na2O - соединение, Na2O +H2O = 2NaOH - соединение, 2NaOH + H2SO4 = Na2SO4 +2H2O - обмена

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5) 4P +5O2 = 2 P2O5

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M(P) = 31 г/моль

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M(P2O5) = 142 г/моль

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n(P2O5) = 7.1/142=0.05 моль

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n(P) = 2 *n(P2O5) = 0.1 моль

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m(P) = 0.1*31=3.1 г

Answer 1

1) a)K2O , CuO
    б)HNO3 , H2SO4
    в)Mg(OH)2 , Cu(OH)2
    г)AlCl3 , BaSO4

2) CuO , Na2O , Fe2O3

3) а) 2Cu + O2 = 2CuO
    б) Cu(OH)2 = CuO + H2O

4) 1) 4Na + O2 = 2Na2O
    2) Na2O + H2O = 2NaOH
    3) 2NaOH + H2SO4 = Na2SO4 + 2H2O

5) 4P + 5O2 = 2P2O5
n=m/M => m=n*M
n(P2O5)=7.1/142=0.05 моль
n(P)=2*n(P2O5)=0.1 моль
m(P)=0.1*31=3,1г
Ответ: m(P)=3.1г