3*3^2x - 7*4^x*3^x +4*4^2x = 0 ! /3^2x
3*3^2x/3^2x - 7*4^x*3^x^/3^2x + 4*4^2x/3^2x = 0
3 - 7*(4/3)^x + 4*(4/3)^2x = 0
нехай (4/3)^х = t, (4/3)^2x = t^2
3-7t+4t^2 = 0 abo 4t^2 - 7t +3 = 0
a=4 b= -7 c=3
D= 49 - 48 = 1
t1 = 7+1/2*4=8/8=1
t2=7-1/2*4=6/8=3/4
1) t1=1
(4/3)^x=1
x=0
2) t2=(3/4)
(4/3)^x=3/4
x=-1
Відповідь: -1, 0