Sin3x *√(4-x^2)=0
4-x^2≥0; (2-x)(2+x)≥0; x=2 lli x=-2
- + -
-------------------(-2)-----------------2-------------------.x
//////////////////////// x⊂[-2;2]
sin 3x=0 ili 4-x^2=0
3x=πn,n-celoe x=-2 ili x=2
x=π/3 *n
-2≤π/3 *n≤2 *3/π
-6/π≤ n≤6/π
-1,7≤n≤1,7
n=-1,0;1
x=-π/3; x=0; x=π/3
Ответ. -π/3; 0; π/3; -2; 2