Решите неравенство: 3(х-1.5)-4 <4х+1.5 решите систему 6х-12>0 2x-3>0 26-x<25 2x-7>13

Question 1

Решите неравенство:
3(х-1.5)-4 <4х+1.5<br>
решите систему
6х-12>0
2x-3>0

26-x<25<br> 2x-7>13

Question 2

1)
$3(x-1.5)-4 \ \textless \ 4x+1.5$
$3x-4.5-4 \ \textless \ 4x+1.5$
$3x-8.5 \ \textless \ 4x+1.5$
$3x-4x \ \textless \ 1.5+8.5$
$-x \ \textless \ 10$
$x\ \textgreater \ -10$
-----------(-10)------------------
////////////////////

Ответ: $(-10;+$ ∞ $)$

2)
$\left \{ {{6x-12\ \textgreater \ 0} \atop {2x-3\ \textgreater \ 0}} \right.$
$\left \{ {{6x\ \textgreater \ 12} \atop {2x\ \textgreater \ 3}} \right.$
$\left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ 1.5}} \right.$
-----------------(2)----------------------
///////////////////////
----------(1.5)--------------------------
////////////////////////////

Ответ: $(2; +$ ∞ $)$

3)
$\left \{ {{26-x\ \textless \ 25} \atop {2x-7\ \textgreater \ 13}} \right.$
$\left \{ {{-x\ \textless \ 25-26} \atop {2x\ \textgreater \ 13+7}} \right.$
$\left \{ {{-x\ \textless \ -1} \atop {2x\ \textgreater \ 20}} \right.$
$\left \{ {{x\ \textgreater \ 1} \atop {x\ \textgreater \ 10}} \right.$
---------(1)--------------------------
///////////////////////////
-------------------(10)--------------
/////////////

Ответ: $(10; +$ ∞ $)$

Luluput_zn · Answer 1 · 2018-05-14T06:46:13+0000

1)
$3(x-1.5)-4 \ \textless \ 4x+1.5$
$3x-4.5-4 \ \textless \ 4x+1.5$
$3x-8.5 \ \textless \ 4x+1.5$
$3x-4x \ \textless \ 1.5+8.5$
$-x \ \textless \ 10$
$x\ \textgreater \ -10$
-----------(-10)------------------
////////////////////

Ответ: $(-10;+$ ∞ $)$

2)
$\left \{ {{6x-12\ \textgreater \ 0} \atop {2x-3\ \textgreater \ 0}} \right.$
$\left \{ {{6x\ \textgreater \ 12} \atop {2x\ \textgreater \ 3}} \right.$
$\left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ 1.5}} \right.$
-----------------(2)----------------------
///////////////////////
----------(1.5)--------------------------
////////////////////////////

Ответ: $(2; +$ ∞ $)$

3)
$\left \{ {{26-x\ \textless \ 25} \atop {2x-7\ \textgreater \ 13}} \right.$
$\left \{ {{-x\ \textless \ 25-26} \atop {2x\ \textgreater \ 13+7}} \right.$
$\left \{ {{-x\ \textless \ -1} \atop {2x\ \textgreater \ 20}} \right.$
$\left \{ {{x\ \textgreater \ 1} \atop {x\ \textgreater \ 10}} \right.$
---------(1)--------------------------
///////////////////////////
-------------------(10)--------------
/////////////

Ответ: $(10; +$ ∞ $)$