A) (1/3)^(4-2*x)=(1/3)^-2
4-2*x=-2
-2*x=-6
x=3
b) 25*5^x+5^x=130
26*5^x=130
5^x=5^1
x=1
c) loq(2)(x^2-2*x)=loq(2)8
x^2-2*x=8
x^2-2*x-8=0
x1,2=(2±√(4+32))/2=(2±6)/2 x1=-2 x2=4
d) (loq(4)x)^2-2*loq(4)x-3=0
Пусть loq(4)x=y
y^2-2*y-3=0
y1,2=(2±√(4+12))/2=(2±4)/2
y1=-1 loq(4)x=loq(4)1/4 x=1/4
y2=3 loq(4)x=loq(4)64 x=64