{ x²+xy-y²=11
{ x-2y=1
{x²+xy-y²=11
{x=1+2y
(1+2y)²+(1+2y)y-y²=11
1+4y+4y²+y+2y²-y²=11
1+5y+5y²=11
1+5y+5y²-11=0
-5(-y²-y+2)=0
-5(-y²+y-2y+2)=0
-5(-y-2)*(y-1_=0
(-y-2)*(y-1)=0
-y-2=0 y=-2
y-1=0 y=1
x=1+2*(-2) x=-3
x=1+2*1 x=3
Ответ: (x₁, y₁)=(-3,-2)
(x₂, y₂)=(3,1)