(sinα/1+cosα)+1+cosα/sinα=2/sinα

Question

(sinα/1+cosα)+1+cosα/sinα=2/sinα

Answer 1

sina/(1+cosa)+(1+cosa)/sina=2/sina

(sina*sina+(1+cosa)^2)/(sina(1+cosa))=2/sina

(sin^2(a)+1+2cosa+cos^2(a))=2/sina

(2+2cosa)/((1+cosa)sina)/2/sina

2(1+cosa)/((1+cosa)sina)=2/sina

2/sina=2/sina