(a^4:3 - b^4:3) : (sqrt 3/a - sqrt 3/b)[Заранее спасибо] ))

Решите задачу:

$\frac{a^{\frac{4}{3}}-b^{\frac{4}{3}}}{\sqrt[3]{a}-\sqrt[3]{b}}=\frac{(a^{\frac{2}{3}}-b^{\frac{2}{3}})(a^{\frac{2}{3}}+b^{\frac{2}{3}})}{a^{\frac{1}{3}}-b^{{\frac{1}{3}}}}=\frac{(a^{\frac{1}{3}}-b^{\frac{1}{3}})(a^{\frac{1}{3}}+b^{\frac{1}{3}})(a^{\frac{2}{3}}+b^{\frac{2}{3}})}{a^{\frac{1}{3}}-b^{{\frac{1}{3}}}}=\\\ =(a^{\frac{1}{3}}+b^{\frac{1}{3}})(a^{\frac{2}{3}}+b^{\frac{2}{3}})$

$\frac{\sqrt[3]{a^4} -\sqrt[3]{a^2b^2}+\sqrt[3]{b^4}}{\sqrt[3]{a}+\sqrt[3]{b}}=\frac{(\sqrt[3]{a^2}+\sqrt[3]{b^2})(\sqrt[3]{a^4} -\sqrt[3]{a^2b^2}+\sqrt[3]{b^4})}{(\sqrt[3]{a^2}+\sqrt[3]{b^2})(\sqrt[3]{a}+\sqrt[3]{b})}=\frac{(\sqrt[3]{a^2})^3+(\sqrt[3]{b^2})^3}{\sqrt[3]{a^2}*\sqrt[3]{a}+\sqrt[3]{b^2}*\sqrt[3]{a}+\sqrt[3]{a}*\sqrt[3]{b^2}+\sqrt[3]{b}*\sqrt[3]{b^2}}=\frac{a^2+b^2}{a+2\sqrt[3]{ab^2}+b}$