Решите уравнение 3x^4-2x^3-3x+2=0
X^3 (3x - 2) - 1 (3x - 2) = 0 (x^3 - 1)(3x - 2) = 0 (x - 1)(x^2 + x + 1) (3x - 2) = 0 x - 1 = 0 x = 1 3x - 2 = 0 3x = 2 x = 2/3 x^2 + x + 1= 0 D = 1 - 4 < 0 нет реш