12/(x²+2x)-3/(x²+2x-2)=1
x²+2x=a
12/a-3/(a-2)=1
a≠0;a≠2
12(a-2)-3*a=a(a-2)
a²-2a-12a+24+3a=0
a²-11a+24=0
a1+a2=11 U a1*a2=24
a1=3⇒x²+2x=3
x²+2x-3=0
x1+x2=-2 U x1*x2=-3⇒x1=-3 U x2=1
a2=8⇒x²+2x=8
x²+2x-8=0
x1+x2=-2 U x1*x2=-8⇒x1=-4 U x2=2
Ответ x={-4;-3;1;2}
(2x-3)(4-x)x²/(x-6)(x²+4x+6)≤0
x²+4x+6>0,D<0<br>x=1,5 x=4 x=0 x=6
+ + _ + _
--------------[0]---------------[1,5]---------------[4]---------------(6)-------------------
x∈[1,5;4] U (6;∞) U {0}