(1-3x)^2=(3x+5)^2-96

Question

(1-3x)^2=(3x+5)^2-96

Answer 1

1-6x+9x^2=9x^2+30x+25-96
-6x-30x=25-96-1
-36x=-72
x=-72/-36
x=2

Answer 2

1-2•1•3x+9x^2-9x^2-2•3x•5-25+96=0
-36x+72=0
-36x=-72
x=2