Tq² 3x -6ctq ( π/2 -3x) =0 ; * * *по формуле приведения : ctq (π/2 - α ) =tqα * * *
tq²3 x -6tq 3x =0 ;
tq 3x *( tq 3x - 6) = 0 ;
[ tq3x = 0 ; tq 3x -6 =0 . ⇔ [ tq3x = 0 ; tq 3x = 6 .
[ 3x =π * n ; 3x = arctq(6) + π * n , n ∈ Z .
[ x =( π/ 3) * n ; x = (1/3)arctq(6) + (π /3)* n , n ∈ Z .
ответ : { π/ 3 * n ; (1/3)arctq(6) + (π /3)* n , n ∈ Z } .