x+1 } \atop { 3x+1> 4x-2}} \right. \left \{ {{3x>6} \atop {-x>-3}} \right. \left \{ {x>2} \atop {x<3}} \right. " alt=" \left \{ {{ 4x-5>x+1 } \atop { 3x+1> 4x-2}} \right. \left \{ {{3x>6} \atop {-x>-3}} \right. \left \{ {x>2} \atop {x<3}} \right. " align="absmiddle" class="latex-formula">
Ответ: (2;3)