10x(x-7)-30<33x-10(x-4) ?

Question

10x(x-7)-30<33x-10(x-4) ?

Answer 1

10x^-70x-30<33x-10x+40<br>10x^-70x-33x+10x-30-40<0<br>10x^-93-70<0<br>b^-4ac=8649-4*10*(-70)=11449. корень 107. 
x1=93+107/2*10=200/20=10.
x2=-14/20=-0,7
Ответ:(-0,7;10)

---