[x/(x-y) + 2xy/(x^2-2xy+y^2)]* {2x/(x+y) - 1} =
= [x/(x-y) + 2xy/(x-y)^2] * [{2x -(x+y)} / (x+y)] =
= [ {x(x-y)+2xy} / (x-y)^2] * [(x-y)/(x+y)] =
= [(x^2-xy+2xy) / (x-y)^2 * [(x-y)/(x+y)]
= [(x^2+xy)] / [(x-y)(x+y)]=
= x(x+y) / [(x-y)(x+y)]=
=x / (x-y) = (-2) / (-2+1) = (-2)/(-1) = 2