(sin^2 1135- sin ^2 35)/(sin350*cos370)

Question

(sin^2 1135- sin ^2 35)/(sin350*cos370)

Answer 1

Sin²1135° = Sin²(180°*6 + 55°) = Sin²55°,
Sin350° = Sin(360° - 10°)= -Sin 10°,
Cos370° = Cos(360° + 10°) = Cos 10°
Числитель = Sin²55° - Sin²35° = (Sin55° - Sin35°)(Sin55° + Sin35°) = 
= 2Sin10°Cos45°*2Sin45°Cos10° = Sin90°*Sin10°Cos10°= Sin10°Cos10°
Знаменатель = -Sin10°Cos10°
Ответ: -1