Выражение: 1/3*m^3*n^2*p^3:(-2/3*m^2*p^2*n^2)
Ответ: -0.5*m*p
Решаем по действиям:
1. 1/3=(1//3)
2. 2/3=(2//3)
3. (1//3)*m^3*n^2*p^3:(-(2//3)*m^2*p^2*n^2)=-(1//3)*m^3*n^2*p^3/(2//3)/m^2/p^2/n^2
4. (1//3)/(2//3)=0.5
5. m^3/m^2=m
m^3/m^2=m^(3-2)
5.1. 3-2=1
-3
_2_
1
6. p^3/p^2=p
p^3/p^2=p^(3-2)
6.1. 3-2=1
-3
_2_
1
7. n^2/n^2=1
Решаем по шагам:
1. (1//3)*m^3*n^2*p^3:(-2/3*m^2*p^2*n^2)
1.1. 1/3=(1//3)
2. (1//3)*m^3*n^2*p^3:(-(2//3)*m^2*p^2*n^2)
2.1. 2/3=(2//3)
3. -(1//3)*m^3*n^2*p^3/(2//3)/m^2/p^2/n^2
3.1. (1//3)*m^3*n^2*p^3:(-(2//3)*m^2*p^2*n^2)=-(1//3)*m^3*n^2*p^3/(2//3)/m^2/p^2/n^2
4. -0.5*m^3*n^2*p^3/m^2/p^2/n^2
4.1. (1//3)/(2//3)=0.5
5. -0.5*m*n^2*p^3/p^2/n^2
5.1. m^3/m^2=m
m^3/m^2=m^(3-2)
5.1.1. 3-2=1
-3
_2_
1
6. -0.5*m*n^2*p/n^2
6.1. p^3/p^2=p
p^3/p^2=p^(3-2)
6.1.1. 3-2=1
-3
_2_
1
7. -0.5*m*p
7.1. n^2/n^2=1