Log( x-1) >= 0 при основании 1/2
Log₁/₂(x-1)≥0 0=log₁/₂(1/2)⁰=log₁/₂1 log₁/₂(x-1)≥log₁/₂ 0<(1/2)<1, знак неравенства меняем<br>{x-1≤1 {x≤2 x-1>0 x>1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -------------|-------------|-------------->X 1 2 / / / / / / / / / / / / / / / / / / / x∈(1;2]
X-1>0⇒x>1 x-1≤1⇒x≤2 x∈(1;2]