Решите систему уравнения {2(3х-у)-5=2х-3у {5-(х-2у)=4у+16

$\left \{ {{2(3x-y)-5=2x-3y} \atop {5-(x-2y)=4y+16}} \right. \\ \left \{ {{6x-2y-5=2x-3y} \atop {5-x+2y=4y+16}} \right. \\ \left \{ {{6x-2x-2y+3y=5} \atop {-x+2y-4y=16-5}} \right. \\ \left \{ {{4x+y=5} \atop {-x-2y=11}} \right. \\ \left \{ {{y=5-4x} \atop {-(x+2y)=11}} \right. \\ \left \{ {{y=5-4x} \atop {x+2y=-11}} \right. \\ \left \{ {{y=5-4x} \atop {x+2(5-4x)=-11}} \right. \\ \left \{ {{y=5-4x} \atop {x+10-8x=-11}} \right. \\ \left \{ {{y=5-4x} \atop {-7x=-11-10}} \right. \\$
$\left \{ {{y=5-4x} \atop {-7x=-21}} \right. \\ \left \{ {{y=5-4x} \atop {x=-21:(-7)}} \right. \\ \left \{ {{y=5-4x} \atop {x=3}} \right. \\ \left \{ {{y=5-4*3} \atop {x=3}} \right. \\ \left \{ {{y=5-12} \atop {x=3}} \right. \\ \left \{ {{y=-7} \atop {x=3}} \right.$
Ответ: (3;-7).